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6t^2/12t=0
Domain of the equation: 12t!=0We multiply all the terms by the denominator
t!=0/12
t!=0
t∈R
6t^2=0
a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$t=\frac{-b}{2a}=\frac{0}{12}=0$
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